WebMar 18, 2024 · Since array is sorted we apply binary search but the length of array is infinite so that we take start = 0 and end = 1 . After that check value of target is greater than the value at end index,if it is true then change newStart = end + 1 and newEnd = end + (end – start +1)*2 and apply binary search . WebHere is another official Solution of LeetCode for this problem: class Solution: def search (self, nums: List [int], target: int) -> int: start, end = 0, len (nums) - 1 while start <= end: mid = start + (end - start) // 2 if nums [mid] == target: return mid elif nums [mid] >= nums [start]: if target >= nums [start] and target < nums [mid]: end ...
Binary Search - Find Index of Target in a Given Array
Web2089. 找出数组排序后的目标下标 - 给你一个下标从 0 开始的整数数组 nums 以及一个目标元素 target 。 目标下标 是一个满足 nums[i] == target 的下标 i 。 将 nums 按 非递减 顺序排序后,返回由 nums 中目标下标组成的列表。如果不存在目标下标,返回一个 空 列表。 WebNov 28, 2024 · 2089 Find Target Indices After Sorting Array (Leetcode Easy) 559 views Nov 27, 2024 Larry solves and analyzes this Leetcode problem as both an interviewer and an interviewee. … javascript programiz online
2089 - Find Target Indices After Sorting Array Leetcode
WebFind Target Indices After Sorting Array Solution In a simplest way, we can sort the array and check each element one by one. If an element = target is found, we can collect the … WebMay 1, 2024 · We have to search for the start and end indexes for the target value. As the array is sorted then it means that all the target values will be seen together. If we will iterate over the input array, then we could check if the element at … WebNov 28, 2024 · A target index is an index i such that nums [i] == target. Return a list of the target indices of nums after sorting nums in non-decreasing order. If there are no target indices, return an empty list. The returned list must be sorted in increasing order. Example 1: Input: nums = [1,2,5,2,3], target = 2 Output: [1,2] javascript print image from url